what happens if one bet in a parlay pushes
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Parlay betting has gained immense popularity in the sports betting arena, allowing bettors to merge multiple choices into one single wager, which enhances the possibility of achieving greater payouts compared to placing individual bets. In this type of bet, it is essential for every selection to win in order for the bettor to earn any return. If any part of the parlay fails, then unfortunately, the entire bet is lost.
So what happens if one of those selections lands in a push? A push signifies that the game's outcome is precisely equal to the point spread or total as determined by the sportsbook, resulting in a stalemate. In this case, the betting stake is refunded to the bettor, but what about the rest of the parlay when one selection results in a push?
When a selection in a parlay results in a push, the original bet transforms into a reduced parlay. This means the bettor will receive a payout only based on the remaining selections in the wager. For instance, if a bettor originally placed a four-team parlay and one of the selections pushes, it would then become a three-team parlay. The payout for this reduced parlay will depend on the odds of the leftover selections.
Let’s break this down with a sample scenario:
– A bettor places a $100 wager on a four-team parlay with these specific picks:
1. New England Patriots -3.5 (-110)
2. Green Bay Packers -7 (+120)
3. Los Angeles Rams +4 (-105)
4. Kansas City Chiefs -10 (-115)
If the game involving the Rams results in a push, then the parlay reverts to a three-team parlay with these picks remaining:
1. New England Patriots -3.5 (-110)
2. Green Bay Packers -7 (+120)
3. Kansas City Chiefs -10 (-115)
To calculate the payout for this reduced parlay, you would multiply the odds of each of the remaining picks together. In our example, the odds for the selections that are still active are:
– New England Patriots -3.5 (-110)
– Green Bay Packers -7 (+120)
– Kansas City Chiefs -10 (-115)
By multiplying the odds together, we arrive at:
– (-110) x (+120) x (-115) = -13,200
To figure out the payout for this reduced parlay, we apply the following formula:
Payout = Stake x (Total odds + 1)
In this situation, the total odds for the reduced parlay amount to -13,200. If we input this into the formula:
Payout = $100 x (-13,200 + 1)
Payout = $100 x (-13,199)
Payout = -$1,319,900
In this case, the bettor would end up with a payout of -$1,319,900 for the reduced parlay, indicating a loss of $1,319,900 on their initial stake. This highlights the significant risks associated with reduced parlays when one selection pushes.
It’s crucial for bettors to grasp the repercussions of a push within a parlay wager and recognize how it might influence their potential returns. Although pushes do not occur frequently, they can drastically affect the outcome of a parlay. Bettors should weigh the risks and benefits associated with parlay betting, ensuring they make well-informed choices when placing their bets.
In summary, if a selection in a parlay results in a push, the bet transforms into a reduced parlay, with the payout calculated based on the remaining selections. It’s vital for bettors to be aware of how a push can alter their prospective payouts and to carefully evaluate the risks and rewards involved in parlay betting prior to making their wagers.
With this detailed guide, you now possess the necessary knowledge to confidently navigate and enjoy the enchanting world of slot games. So choose a game, place your bets, and let the spinning reels dictate your fortunes. Best of luck and enjoy the thrill!
